(x+1)+(x+2)+(x+3)+….+(x+10)=57 giúp mình với iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

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(x+1)+(x+2)+(x+3)+….+(x+10)=57 giúp mình với iiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiiii

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Lyla 12 phút 2021-09-10T12:57:00+00:00 2 Answers 0 views 0

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    0
    2021-09-10T12:58:24+00:00

    $\text{(x + 1) + (x + 2) + (x + 3) + … + (x + 10) = 57}$

    $\text{x × 10 + (1 + 2 + 3 + … + 10) = 57}$
    $\text{x × 10 + 55 = 57}$
    $\text{x × 10 = 57 – 55}$
    $\text{x × 10 = 2}$
    $\text{x = 2 : 10}$
    $\text{x = 0,2}$

    0
    2021-09-10T12:58:58+00:00

    (x+1)+(x+2)+(x+3)+….+(x+10) = 57

    ⇔ x + 1 + x + 2 + x + 3 +…..+ x + 10 = 57

    ⇔ 10x + ( 1 + 2 + …… + 10 ) = 57

    ⇔ 10x + 55 = 57

    ⇔ 10x = 2

    ⇒ x = 0,2

     

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