1/ ( x^2-5) (x+3) 2/(x+4) (x-x^2) 3/ (12x-5) (4x-1) 4/(3x-7) (1-16x)

0 bình luận về “1/ ( x^2-5) (x+3) 2/(x+4) (x-x^2) 3/ (12x-5) (4x-1) 4/(3x-7) (1-16x)”

1. 1/ ( x²-5) (x+3)

   = x³+3x²-5x+15

   2/ (x+4) (x-x²)

   = x²-x³+4x-4x²

   = 2x²-x³+4x

   3/ (12x-5) (4x-1)

   = 48x²-12x-20x+5

   = 48x²-32x+5

   4/(3x-7) (1-16x)

   = 3x-18x²-7+112x

   = 115x-18x²-7

   Trả lời

2. Đáp án:

    

   Giải thích các bước giải:

   $1/ (x^2-5)(x+3)$

   $=x^2(x+3)-5(x+3)$

   $=x^3+3x^2-5x-15$

   $2/ (x+4)(x-x^2)$

   $=x(x-x^2)+4(x-x^2)$

   $=x^2-x^3+4x-4x^2$

   $=4x-x^3-3x^2$

   $3/ (12x-5)(4x-1)$

   $=12x(4x-1)-5(4x-1)$

   $=48x^2-12x-20x+5$

   $=48x^2-32x+5$

   $4/ (3x-7)(1-16x)$

   $=3x(1-16x)-7(1-16x)$

   $=3x-48x^2-7+102x$

   $=105x-48x^2-7$

   Trả lời