1) a) ( 3x + y – z ) – ( 4x – 2y + 6z ) b) K=2x × ( -3x + 5 ) + 3x × ( 2x – 12 ) + 26x

0 bình luận về “1) a) ( 3x + y – z ) – ( 4x – 2y + 6z ) b) K=2x × ( -3x + 5 ) + 3x × ( 2x – 12 ) + 26x”

1. Đáp án: $a,$ $=-x+3y-7z$

               $ b,$ $=0$

    

   Giải thích các bước giải:

   $a)(3x+y-z )-(4x-2y+6z)$

   $=3x+y-z-4x+2y-6z$

   $=-x+3y-7z$

   $b, K=2x(-3x+5 )+3x(2x-12)+26x$

   $=-6x+10x+6$$x^{2}$ $-36x+26x$

   $=$$-6$$x^{2}$$+10x +6x^{2} -36x+26x$

   $=0$

    

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2. $a) (  3x + y – z ) – ( 4x – 2y + 6z )\\=3x+y-z-4x+2y-6z\\=-x+3y-7z\\b) K=2x . ( -3x + 5 ) + 3x . ( 2x – 12 ) + 26x\\K=-6x^{2}+10x+6x^{2}-36x+26x=0$

   Trả lời