(1+ $\frac{8}{10}$ ).(1+ $\frac{8}{22}$ ).(1+ $\frac{8}{36}$)…(1+ $\frac{8}{8352}$ )

0 bình luận về “(1+ $\frac{8}{10}$ ).(1+ $\frac{8}{22}$ ).(1+ $\frac{8}{36}$)…(1+ $\frac{8}{8352}$ )”

1. Đáp án:

   $\dfrac{33}{4}$ 

   Giải thích các bước giải:

   $\displaystyle \begin{array}{{>{\displaystyle}l}} \left( 1+\dfrac{8}{10}\right)\left( 1+\dfrac{8}{22}\right)\left( 1+\dfrac{8}{36}\right) …\left( 1+\dfrac{8}{8352}\right)\\ =\dfrac{18}{10} .\dfrac{30}{22} .\dfrac{44}{36} …\dfrac{8360}{8352}\\ =\dfrac{2.9.3.10.4.11…88.95}{1.10.2.11.3.12…87.96}\\ =\dfrac{( 2.3.4…88)( 9.10.11…95)}{( 1.2.3…87)( 10.11…96)}\\ =\dfrac{9.88}{96} =\dfrac{33}{4} \end{array}$

   Trả lời

2. (1+8/10).1+8/22).(1+8/36)…(1+8/8352)

   =18.30.44…8360/10.22.36…8352

   =9.2.10.3.11.4…95.88/10.11.2.12.3…96.87

   =(9.10.11…95).(2.3.4…88)/(10.11.12…96).(2.3.4…87)

   =9.88/96

   =792/96

   =33/4

   Bài này mik làm ở lớp rồi nha

    

   Trả lời