|x+13|-|-10|=-8+2 |x-11|-(-5+6)=-|-5| |x+11|-|-3|+|-5|=8 |x-3|-(5-7+|-3|=|5-7| 5-|x-1|=3-|4+5-7| 51-|x-1|=-(4-51+3| -12+3-|x+2|=7-12 14-(5-6)-|x-3|=14

0 bình luận về “|x+13|-|-10|=-8+2 |x-11|-(-5+6)=-|-5| |x+11|-|-3|+|-5|=8 |x-3|-(5-7+|-3|=|5-7| 5-|x-1|=3-|4+5-7| 51-|x-1|=-(4-51+3| -12+3-|x+2|=7-12 14-(5-6)-|x-3|=14”

1. `a)|x+13|-|-10|=-8+2`

   `→|x+13|-10=-6`

   `→|x+13|=-6+10`

   `→|x+13|=4`

   `→` \(\left[ \begin{array}{l}x+13=4\\x+13=-4\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=-9\\x=-17\end{array} \right.\) 

   Vậy `x∈{-9;-17}`

   `b)|x-11|-(-5+6)=-|-5|`

   `→|x-11|-1=-5`

   `→|x-11|=-4`

   `|x-11|≥0→x∈∅`

   Vậy `x∈∅`

   `c)|x+11|-|-3|+|-5|=8`

   `→|x+11|-3+5=8`

   `→|x+11|=8+3-5`

   `→|x+11|=6`

   `→` \(\left[ \begin{array}{l}x+11=6\\x+11=-6\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=-5\\x=-17\end{array} \right.\) 

   Vậy `x∈{-5;-17}`

   `d)|x-3|-(5-7+|-3|=|5-7|`

   `→|x-3|-1=2`

   `→|x-3|=3`

   `→` \(\left[ \begin{array}{l}x-3=3\\x-3=-3\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=6\\x=0\end{array} \right.\) 

   Vậy `x∈{6;0}`

   `e)5-|x-1|=3-|4+5-7|`

   `→5-|x-1|=1`

   `→|x-1|=4`

   `→` \(\left[ \begin{array}{l}x-1=4\\x-1=-4\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=5\\x=-3\end{array} \right.\) 

   Vậy `x∈{5;-3}`

   `f)51-|x-1|=-(4-51+3)`

   `→51-|x-1|=44`

   `→|x-1|=7`

   `→` \(\left[ \begin{array}{l}x-1=7\\x-1=-7\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=8\\x=-6\end{array} \right.\) 

   Vậy `x∈{8;-6}`

   `g)-12+3-|x+2|=7-12`

   `→-9-|x+2|=-5`

   `→|x+1|=-9-(-5)`

   `→|x+1|=-4`

   `|x+1|≥0→x∈∅`

   `h)14-(5-6)-|x-3|=14`

   `→15-|x-3|=14`

   `→|x-3|=15-14`

   `→|x-3|=1`

   `→` \(\left[ \begin{array}{l}x-3=1\\x-3=-1\end{array} \right.\) 

   `→` \(\left[ \begin{array}{l}x=4\\x=2\end{array} \right.\) 

   Vậy `x∈{4;2}`

   `i)23-(7-4)-|x+7|=1-(-23)`

   `→20-|x+7|=24`

   `→|x+7|=20-24`

   `→|x+7|=-4`

   `|x+7|≥0→x∈∅`

    

   Trả lời