## |x+13|-|-10|=-8+2 |x-11|-(-5+6)=-|-5| |x+11|-|-3|+|-5|=8 |x-3|-(5-7+|-3|=|5-7| 5-|x-1|=3-|4+5-7| 51-|x-1|=-(4-51+3| -12+3-|x+2|=7-12 14-(5-6)-|x-3|=14

Question

|x+13|-|-10|=-8+2
|x-11|-(-5+6)=-|-5|
|x+11|-|-3|+|-5|=8
|x-3|-(5-7+|-3|=|5-7|
5-|x-1|=3-|4+5-7|
51-|x-1|=-(4-51+3|
-12+3-|x+2|=7-12
14-(5-6)-|x-3|=14
23-(7-4)-|x+7|=1-(-23)
Thanks

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1 tháng 2021-11-08T21:37:07+00:00 1 Answers 4 views 0

1. a)|x+13|-|-10|=-8+2

→|x+13|-10=-6

→|x+13|=-6+10

→|x+13|=4

→ $$\left[ \begin{array}{l}x+13=4\\x+13=-4\end{array} \right.$$

→ $$\left[ \begin{array}{l}x=-9\\x=-17\end{array} \right.$$

Vậy x∈{-9;-17}

b)|x-11|-(-5+6)=-|-5|

→|x-11|-1=-5

→|x-11|=-4

|x-11|≥0→x∈∅

Vậy x∈∅

c)|x+11|-|-3|+|-5|=8

→|x+11|-3+5=8

→|x+11|=8+3-5

→|x+11|=6

→ $$\left[ \begin{array}{l}x+11=6\\x+11=-6\end{array} \right.$$

→ $$\left[ \begin{array}{l}x=-5\\x=-17\end{array} \right.$$

Vậy x∈{-5;-17}

d)|x-3|-(5-7+|-3|=|5-7|

→|x-3|-1=2

→|x-3|=3

→ $$\left[ \begin{array}{l}x-3=3\\x-3=-3\end{array} \right.$$

→ $$\left[ \begin{array}{l}x=6\\x=0\end{array} \right.$$

Vậy x∈{6;0}

e)5-|x-1|=3-|4+5-7|

→5-|x-1|=1

→|x-1|=4

→ $$\left[ \begin{array}{l}x-1=4\\x-1=-4\end{array} \right.$$

→ $$\left[ \begin{array}{l}x=5\\x=-3\end{array} \right.$$

Vậy x∈{5;-3}

f)51-|x-1|=-(4-51+3)

→51-|x-1|=44

→|x-1|=7

→ $$\left[ \begin{array}{l}x-1=7\\x-1=-7\end{array} \right.$$

→ $$\left[ \begin{array}{l}x=8\\x=-6\end{array} \right.$$

Vậy x∈{8;-6}

g)-12+3-|x+2|=7-12

→-9-|x+2|=-5

→|x+1|=-9-(-5)

→|x+1|=-4

|x+1|≥0→x∈∅

h)14-(5-6)-|x-3|=14

→15-|x-3|=14

→|x-3|=15-14

→|x-3|=1

→ $$\left[ \begin{array}{l}x-3=1\\x-3=-1\end{array} \right.$$

→ $$\left[ \begin{array}{l}x=4\\x=2\end{array} \right.$$

Vậy x∈{4;2}

i)23-(7-4)-|x+7|=1-(-23)

→20-|x+7|=24

→|x+7|=20-24

→|x+7|=-4

|x+7|≥0→x∈∅