Toán { ( 2/193 – 3/386) x 193/17 + 33/34 } : { ( 7/1931 + 11/ 3862} x 1931/25 + 9/2} 09/09/2021 By Piper { ( 2/193 – 3/386) x 193/17 + 33/34 } : { ( 7/1931 + 11/ 3862} x 1931/25 + 9/2}
$\left [ \left ( \dfrac{2}{193}-\dfrac{3}{386} \right )*\dfrac{193}{17}+\dfrac{33}{34} \right ]:\left [ \left ( \dfrac{7}{1931}+\dfrac{11}{3862} \right )*\dfrac{1931}{25}+\dfrac{9}{2} \right ]\\=\left ( \dfrac{1}{386}*\dfrac{193}{17}+\dfrac{33}{34} \right ):\left ( \dfrac{25}{3862}*\dfrac{1931}{25}+\dfrac{9}{2} \right )\\=\left ( \dfrac{1}{2}*\dfrac{1}{17}+\dfrac{33}{34}\right ):\left ( \dfrac{1}{2}+\dfrac{9}{2} \right )\\=\left ( \dfrac{1}{34}+\dfrac{33}{34} \right ):5=1:5=0,2$ * là dấu nhân nhé Trả lời
$((\frac{2}{193} – \frac{3}{386}) × \frac{193}{17} + \frac{33}{34})÷((\frac{7}{1931} + \frac{11}{3862}) × \frac{1931}{25} + \frac{9}{2})$ = $((\frac{4}{386} – \frac{3}{386}) × \frac{193}{17} + \frac{33}{34})÷((\frac{14}{3862} + \frac{11}{3862}) × \frac{1931}{25} + \frac{9}{2})$ = $(\frac{4-3}{386} × \frac{193}{17} + \frac{33}{34})÷(\frac{14+11}{3862} × \frac{1931}{25} + \frac{9}{2})$ = $(\frac{1}{386} × \frac{193}{17} + \frac{33}{34})÷(\frac{25}{3862} × \frac{1931}{25} + \frac{9}{2})$ = $(\frac{1 × 193}{386 × 17} + \frac{33}{34})÷(\frac{25 × 1931}{3862 × 25} + \frac{9}{2})$ = $(\frac{1}{34} + \frac{33}{34})÷(\frac{1}{2} + \frac{9}{2})$ = $\frac{1+33}{34}÷\frac{1+9}{2}$ = $1÷5$ = $\frac{1}{5}$ Trả lời
$\left [ \left ( \dfrac{2}{193}-\dfrac{3}{386} \right )*\dfrac{193}{17}+\dfrac{33}{34} \right ]:\left [ \left ( \dfrac{7}{1931}+\dfrac{11}{3862} \right )*\dfrac{1931}{25}+\dfrac{9}{2} \right ]\\=\left ( \dfrac{1}{386}*\dfrac{193}{17}+\dfrac{33}{34} \right ):\left ( \dfrac{25}{3862}*\dfrac{1931}{25}+\dfrac{9}{2} \right )\\=\left ( \dfrac{1}{2}*\dfrac{1}{17}+\dfrac{33}{34}\right ):\left ( \dfrac{1}{2}+\dfrac{9}{2} \right )\\=\left ( \dfrac{1}{34}+\dfrac{33}{34} \right ):5=1:5=0,2$
* là dấu nhân nhé
$((\frac{2}{193} – \frac{3}{386}) × \frac{193}{17} + \frac{33}{34})÷((\frac{7}{1931} + \frac{11}{3862}) × \frac{1931}{25} + \frac{9}{2})$
= $((\frac{4}{386} – \frac{3}{386}) × \frac{193}{17} + \frac{33}{34})÷((\frac{14}{3862} + \frac{11}{3862}) × \frac{1931}{25} + \frac{9}{2})$
= $(\frac{4-3}{386} × \frac{193}{17} + \frac{33}{34})÷(\frac{14+11}{3862} × \frac{1931}{25} + \frac{9}{2})$
= $(\frac{1}{386} × \frac{193}{17} + \frac{33}{34})÷(\frac{25}{3862} × \frac{1931}{25} + \frac{9}{2})$
= $(\frac{1 × 193}{386 × 17} + \frac{33}{34})÷(\frac{25 × 1931}{3862 × 25} + \frac{9}{2})$
= $(\frac{1}{34} + \frac{33}{34})÷(\frac{1}{2} + \frac{9}{2})$
= $\frac{1+33}{34}÷\frac{1+9}{2}$
= $1÷5$ = $\frac{1}{5}$