3x^2-11x+6 x^3-2x^2-9x+18 2x^3-3x^2-2x+3 Question 3x^2-11x+6 x^3-2x^2-9x+18 2x^3-3x^2-2x+3 in progress 0 Toán Serenity 1 năm 2021-07-20T22:45:13+00:00 2021-07-20T22:45:13+00:00 2 Answers 7 views 0
Answers ( )
Giải thích các bước giải:
`3x^2-11x+6`
`=(3x^2-9x)-(2x-6)`
`=3x(x-3)-2(x-3)`
`=(3x-2)(x-3)`
`x^3-2x^2-9x+18`
`=(x^3+3x^2)-(5x^2+15x)+(6x+18)`
`=x^2(x+3)-5x(x+3)+6(x+3)`
`=(x+3)(x^2-5x+6)`
`=(x+3)[(x^2-2x)-(3x-6)]`
`=(x+3)[(x(x-2)-3(x-2)]`
`=(x+3)(x-2)(x-3)`
`2x^3-3x^2-2x+3`
`=(2x^3-3x^2)-(2x-3)`
`=x^2(2x-3)-(2x-3)`
`=(x^2-1)(2x-3)`
`=(x-1)(x+1)(2x-3)`
Đáp án:
Giải thích các bước giải:
a) `3x^2-11x+6`
`=(3x^2-9x)-(2x-6)`
`=3x(x-3)-2(x-3)`
`=(3x-2)(x-3)`
b) `x^3-2x^2-9x+18`
`=(x^3+3x^2)-(5x^2+15x)+(6x+18)`
`=x^2(x+3)-5x(x+3)+6(x+3)`
`=(x+3)(x^2-5x+6)`
`=(x+3)[(x^2-2x)-(3x-6)]`
`=(x+3)[(x(x-2)-3(x-2)]`
`=(x+3)(x-2)(x-3)`
c) `2x^3-3x^2-2x+3`
`=(2x^3-3x^2)-(2x-3)`
`=x^2(2x-3)-(2x-3)`
`=(x^2-1)(2x-3)`
`=(x-1)(x+1)(2x-3)`