– ( x + 3 ) ( x – 4 ) + ( x – 1 ) ( x + 1 ) = 7 mn giúp mik nha kop nguyên tổ mik bị đánh á lm ơn giúp mik nha
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$-(x+3)(x-4)+(x-1)(x+1)=7$
$↔ -(x^2-4x+3x-12)+x^2-1-7=0$
$↔ (-x^2+x^2)+x+12-1-7=0$
$↔ x=-4$