Toán x+ 4/9.13 + 4/13.17 + 4//17.21 + …… + 4/41.45 = 10 09/09/2021 By aihong x+ 4/9.13 + 4/13.17 + 4//17.21 + …… + 4/41.45 = 10
Đáp án: $x=\dfrac{446}{45}$ Giải thích các bước giải: $x+\dfrac{4}{9.13}+\dfrac{4}{13.17}+….+\dfrac{4}{41.45} = 10$ $⇔x+\dfrac{1}{9}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{17}+….+\dfrac{1}{41}-\dfrac{1}{45} = 10$ $⇔x+\dfrac{1}{9}-\dfrac{1}{45} = 10$ $⇔x=\dfrac{446}{45}$ Vậy $x=\dfrac{446}{45}$ Trả lời
`x+ 4/(9.13) + 4/(13.17) + 4/(17.21) + …… + 4/(41.45) = 10` `=>x+ (4/(9.13) + 4/(13.17) + 4/(17.21) + …… + 4/(41.45) )= 10` `=>x+ (1/9-1/13 + 1/13-1/17 + 1/17-1/21 + …… + 1/41-1/45 )= 10` `=>x+ (1/9-1/45 )= 10` `=>x+ 4/45= 10` `=>x=9 41/45` Học tốt!!! #nocopy Trả lời
Đáp án: $x=\dfrac{446}{45}$
Giải thích các bước giải:
$x+\dfrac{4}{9.13}+\dfrac{4}{13.17}+….+\dfrac{4}{41.45} = 10$
$⇔x+\dfrac{1}{9}-\dfrac{1}{13}+\dfrac{1}{13}-\dfrac{1}{17}+….+\dfrac{1}{41}-\dfrac{1}{45} = 10$
$⇔x+\dfrac{1}{9}-\dfrac{1}{45} = 10$
$⇔x=\dfrac{446}{45}$
Vậy $x=\dfrac{446}{45}$
`x+ 4/(9.13) + 4/(13.17) + 4/(17.21) + …… + 4/(41.45) = 10`
`=>x+ (4/(9.13) + 4/(13.17) + 4/(17.21) + …… + 4/(41.45) )= 10`
`=>x+ (1/9-1/13 + 1/13-1/17 + 1/17-1/21 + …… + 1/41-1/45 )= 10`
`=>x+ (1/9-1/45 )= 10`
`=>x+ 4/45= 10`
`=>x=9 41/45`
Học tốt!!!
#nocopy