(x-49)/50+(x-50)/49=(x-39)/60+(x-60)/39 giúp mk nhé

Question

(x-49)/50+(x-50)/49=(x-39)/60+(x-60)/39
giúp mk nhé

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Reagan 3 tháng 2021-08-29T19:08:51+00:00 2 Answers 4 views 0

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    0
    2021-08-29T19:10:40+00:00

    `(x-49)/50+(x-50)/49=(x-39)/60+(x-60)/39`

    `⇔((x-49)/50-1)+((x-50)/49-1)=((x-39)/60-1)+((x-60)/39-1)`

    `⇔(x-99)/50+(x-99)/49=(x-99)/60+(x-99)/39`

    `⇔(x-99)(1/50+1/49-1/60-1/39)=0`

    `⇔x-99=0` `(vì\ 1/50+1/49-1/60-1/39\ne0)`

    `⇔x=99`

    Vậy $S=\{99\}$.

     

    0
    2021-08-29T19:10:49+00:00

    Đáp án: $x=99$

    `(x-49)/50+(x-50)/49=(x-39)/60+(x-60)/39`

    `⇔(x-49)/50+(x-50)/49-(x-39)/60-(x-60)/39=0`

    `⇔((x-49)/50-1)+((x-50)/49-1)-((x-39)/60-1)-((x-60)/39-1)=0`

    `⇔(x-99)/50+(x-99)/49-(x-99)/60-(x-99)/39=0`

    `⇔(x-99)(1/50+1/49-1/60-1/39)=0`

    `⇔x-99=0` (do `1/50+1/49-1/60-1/39` khác 0)

    `⇔x=99`

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