(x-5) ²=25

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(x-5) ²=25

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Daisy 1 tháng 2021-08-11T04:37:29+00:00 2 Answers 3 views 0

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    0
    2021-08-11T04:38:37+00:00

    $(x-5)^2=25$

    $TH1: (x-5)^2=(5)^2$    $TH2: (x-5)^2=(-5)^2$

    $⇒x-5=5$                      $⇒x-5=-5$

    $⇒x=5+5$                     $⇒x=-5+5$

    $⇒x=10$                          $⇒x=0$

    Vậy `x∈{10;0}`

    0
    2021-08-11T04:39:13+00:00

    Đáp án:

      (x – 5)² = 25

    ⇔ \(\left[ \begin{array}{l}(x-5)²=5²\\(x-5)²=(-5)²\end{array} \right.\) 

    ⇔ \(\left[ \begin{array}{l}x-5=5\\x-5=-5\end{array} \right.\) 

    ⇔ \(\left[ \begin{array}{l}x=10\\x=0\end{array} \right.\) 

     

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