Toán (x-5).(x ²-4)=0 giúp mk vs nha mk ko bt làm 01/10/2021 By Jasmine (x-5).(x ²-4)=0 giúp mk vs nha mk ko bt làm
(x-5).($x^{2}$ -4)=0 ⇔\(\left[ \begin{array}{l}x-5=0\\x^{2} -4=0\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=5\\x^{2} =4\end{array} \right.\) ⇔\(\left[ \begin{array}{l}x=5\\x=±2\end{array} \right.\) . Vậy x ∈(5;±2) Trả lời
$(x-5)(x^2-4)=0 \\\Leftrightarrow \left[\begin{matrix}x-5=0 & \\ x^2-4=0 & \end{matrix}\right. \\\Leftrightarrow \left[\begin{matrix}x=5 & \\ x=2;x=-2 & \end{matrix}\right.$ Trả lời
(x-5).($x^{2}$ -4)=0
⇔\(\left[ \begin{array}{l}x-5=0\\x^{2} -4=0\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=5\\x^{2} =4\end{array} \right.\)
⇔\(\left[ \begin{array}{l}x=5\\x=±2\end{array} \right.\) .
Vậy x ∈(5;±2)
$(x-5)(x^2-4)=0 \\
\Leftrightarrow \left[\begin{matrix}
x-5=0 & \\
x^2-4=0 &
\end{matrix}\right. \\
\Leftrightarrow \left[\begin{matrix}
x=5 & \\
x=2;x=-2 &
\end{matrix}\right.$