(x-5).(x ²-4)=0 giúp mk vs nha mk ko bt làm

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(x-5).(x ²-4)=0
giúp mk vs nha mk ko bt làm

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Jasmine 1 năm 2021-10-01T02:17:44+00:00 2 Answers 5 views 0

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    0
    2021-10-01T02:19:26+00:00

    (x-5).($x^{2}$ -4)=0

    ⇔\(\left[ \begin{array}{l}x-5=0\\x^{2} -4=0\end{array} \right.\) 

    ⇔\(\left[ \begin{array}{l}x=5\\x^{2} =4\end{array} \right.\) 

    ⇔\(\left[ \begin{array}{l}x=5\\x=±2\end{array} \right.\) .

    Vậy x ∈(5;±2)

     

    0
    2021-10-01T02:19:26+00:00

    $(x-5)(x^2-4)=0 \\
    \Leftrightarrow \left[\begin{matrix}
    x-5=0 & \\ 
    x^2-4=0 & 
    \end{matrix}\right. \\
    \Leftrightarrow \left[\begin{matrix}
    x=5 & \\ 
    x=2;x=-2 & 
    \end{matrix}\right.$

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