Toán 6x (3x+5) – 2x (3x-2) + (17-x) (x-1) + x (x-18) =0 25/08/2021 By Jade 6x (3x+5) – 2x (3x-2) + (17-x) (x-1) + x (x-18) =0
Bạn tham khảo: $6x (3x+5) – 2x (3x-2) + (17-x) (x-1) + x (x-18) =0$ $=18x^2 + 30x – 6x^2 – 4x + 17x + 17 + x^2 + x – x^2 – 18x = 0$ $= 18x^2 + 30x + 17x – 4x – 18x+ x^2 – x^2 + x =0$ $ =18x^2 + 25 + 0 + x = 0$ $=18x^2 + x + 25 = 0$ $= 18x^2 + x = -25$ Trả lời
Đáp án:
xin hay nhất nha bạn
Giải thích các bước giải:
Bạn tham khảo:
$6x (3x+5) – 2x (3x-2) + (17-x) (x-1) + x (x-18) =0$
$=18x^2 + 30x – 6x^2 – 4x + 17x + 17 + x^2 + x – x^2 – 18x = 0$
$= 18x^2 + 30x + 17x – 4x – 18x+ x^2 – x^2 + x =0$
$ =18x^2 + 25 + 0 + x = 0$
$=18x^2 + x + 25 = 0$
$= 18x^2 + x = -25$