A=1+1/2-(1+2)+1/3-(1+2+3)+1/4-( 1+2+3+4)+…+1/16-(1+2+3+…+16)

Question

A=1+1/2-(1+2)+1/3-(1+2+3)+1/4-( 1+2+3+4)+…+1/16-(1+2+3+…+16)

in progress 0
Peyton 2 tháng 2021-10-15T08:50:08+00:00 2 Answers 9 views 0

Answers ( )

    0
    2021-10-15T08:51:13+00:00

    Ta có:

    ` A= 1+1/2 . (1+2)+3/1 . (1+2+3)+…+1/16 . (1+2+3+…+16) `

    ` <=> A = 1+ 1/2 . 3 +…+1/16 . 136 `

    ` <=> A =1+1,5+2+…+8,5 `

    ` <=> A = \frac{ (8,5 + 1).[(8,5 – 1) : 0,5 + 1] }{2} `

    ` <=> A = \frac{152}{2} `

    ` <=> A = 76 `

    0
    2021-10-15T08:51:15+00:00

    Đáp án:

     

    Giải thích các bước giải:

    A= 1+1/2(1+2)+3/1(1+2+3)+ … +1/16(1+2+3+…+16)

    A= 1+ 1/2 . 3+…+1/16 . 136

    A=1+1,5+2+…+8,5

    A= ___( 8,5+1 )_[ (8,5-1) : 0,5+1 ]___ = 76

                                 2

Leave an answer

Browse

35:5x4+1-9:3 = ? ( )