A = 1 + 3 + 3 ¬2 + 3 ¬4 + … + 3 ¬100

Question

A = 1 + 3 + 3 ¬2 + 3 ¬4 + … + 3 ¬100

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Amaya 2 tuần 2021-09-06T03:36:17+00:00 2 Answers 8 views 0

Answers ( )

    0
    2021-09-06T03:37:21+00:00

    Đáp án:

     

    Giải thích các bước giải:

    A=1+3+3^2+………+3^100

    3A=3+3^2+3^3+………..+3^101

    3A-A=(3+3^2+3^3+………..+3^101)

              -(1+3+3^2+……….+3^100)

    2A=3^101-1

      A=3^101-1:2

     

     

    0
    2021-09-06T03:38:00+00:00

    A=1+3+32+…+3100

    ⇒A.3=3+32+33+…+3101

    ⇒A.3-A=3+32+33+…+3101-1-3-32-…-3100

    ⇒A.2=3101-1

    ⇒ A = $\frac{3101-1}{2}$ 

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