Toán a) (2x^2 – 10x) + x – 5 = 0 Nhanh lên các bn, anh, chị 09/09/2021 By Adalyn a) (2x^2 – 10x) + x – 5 = 0 Nhanh lên các bn, anh, chị
`(2x^2 – 10x )+ x – 5 = 0` `⇔ 2x^2 – 10x + x – 5 = 0` `⇔ 2x^2 – 9x – 5 = 0` `⇔ 2x^2 + x – 10x – 5 = 0` `⇔ ( 2x^2 + x ) + (-10x – 5 ) = 0` `⇔ x(2x + 1) – 5(2x – 1) = 0` `⇔ (x – 5)(2x + 1) = 0` `⇔` \(\left[ \begin{array}{l}x-5=0\\2x +1=0\end{array} \right.\) `⇔` \(\left[ \begin{array}{l}x=5\\x=-\frac{1}{2}\end{array} \right.\) Vậy `S = { 5 ; -1/2}` Trả lời
$\text{Đáp án + Giải thích các bước giải:}$ `a//(2x^{2}-10x)+x-5=0` `=>2x(x-5)+(x-5)=0` `=>(x-5)(2x+1)=0` `=>` \(\left[ \begin{array}{l}x-5=0\\2x+1=0\end{array} \right.\) `=>` \(\left[ \begin{array}{l}x=5\\x=-\dfrac{1}{2}\end{array} \right.\) `\text{Vậy}` `x∈{5;-(1)/(2)}` Trả lời
`(2x^2 – 10x )+ x – 5 = 0`
`⇔ 2x^2 – 10x + x – 5 = 0`
`⇔ 2x^2 – 9x – 5 = 0`
`⇔ 2x^2 + x – 10x – 5 = 0`
`⇔ ( 2x^2 + x ) + (-10x – 5 ) = 0`
`⇔ x(2x + 1) – 5(2x – 1) = 0`
`⇔ (x – 5)(2x + 1) = 0`
`⇔` \(\left[ \begin{array}{l}x-5=0\\2x +1=0\end{array} \right.\)
`⇔` \(\left[ \begin{array}{l}x=5\\x=-\frac{1}{2}\end{array} \right.\)
Vậy `S = { 5 ; -1/2}`
$\text{Đáp án + Giải thích các bước giải:}$
`a//(2x^{2}-10x)+x-5=0`
`=>2x(x-5)+(x-5)=0`
`=>(x-5)(2x+1)=0`
`=>` \(\left[ \begin{array}{l}x-5=0\\2x+1=0\end{array} \right.\)
`=>` \(\left[ \begin{array}{l}x=5\\x=-\dfrac{1}{2}\end{array} \right.\)
`\text{Vậy}` `x∈{5;-(1)/(2)}`