a)28-(x-37)=15 b)(x+13):5=12 c)12.(x-1)=108

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1. a)       28 – (x – 37) = 15

   <=> 28 – x + 37 – 15 =0

   <=> 50 – x =0

   <=> x = 50

   b) (x + 13) : 5 =12

   <=> x + 13 = 60

   <=> x = 47

   c)12 . ( x – 1) = 108

   <=> 12x – 12 -108 =0

   <=> 12x – 120 = 0

   <=> 12x =120

   <=> x = 10

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2. a 28 – (x – 37) = 15

   <=> 28 – x + 37 – 15 =0

   <=> 50 – x =0

   <=> x = 50

   b (x + 13) : 5 =12

   <=> x + 13 = 60

   <=> x = 47

   c 12 . ( x – 1) = 108

   <=> 12x – 12 -108 =0

   <=> 12x – 120 = 0

   <=> 12x =120

   <=> x = 10

    

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