a) 30-2x=x-2021 b) x(2x-1)-2(x+2)^2=2019 c) (x-3)^2-2021x+6063=0 d) 12/x^2-4 – x+1/x+2 + x+7/x+2=0 e) 7x/6 +2x < 16-x/5 -12

Question

a) 30-2x=x-2021
b) x(2x-1)-2(x+2)^2=2019
c) (x-3)^2-2021x+6063=0
d) 12/x^2-4 – x+1/x+2 + x+7/x+2=0
e) 7x/6 +2x < 16-x/5 -12

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Adalyn 3 tháng 2021-09-17T02:34:22+00:00 1 Answers 23 views 0

Answers ( )

    0
    2021-09-17T02:35:38+00:00

    `a,\ 30-2x=x-2021`
    `<=>30-2x-x+2021=0`
    `<=>2025-3x=0`
    `<=>-3x=-2025`
    `<=>x=2025/3`
    Vậy…

    `b,\ x(2x-1)-2(x+2)^2=2019`
    `<=>2x^2-1-2(x^2+4x+4)=2019`
    `<=>2x^2-1-2x^2-8x-8=2019`
    `<=>-8x-9=2019`
    `<=>-8x=2028`
    `<=>x=(-507)/2`
    Vậy…

    `c, (x-3)^2-2021x+6063=0`
    `<=>x^2-6x+9-2021x+6063=0`
    `<=>x^2−2027x+6072=0`
    `<=>(x−2024)(x−3)=0`
    `<=>(x−2024)(x−3)=0`
    $⇔\begin{cases}x−2024=0 \\ x−3=0 \end{cases}$
    $⇔\begin{cases}x=2024\\ x=3 \end{cases}$
    Vậy…

    `d,\ 12/(x^2-4)-(x+1)/(x+2)+(x+7)/(x+2)=0`
    `<=>12/(x^2-4)-((x+1)(x-2))/(x^2-4)+((x+7)(x-2))/(x+2)=0`
    `<=>12-(x+1)(x-2)+(x+7)(x-2)=0`
    `<=>12-(x^2−x−2)+x^2+5x−14=0`
    `<=>12-x^2+x+2+x^2+5x−14=0`
    `<=>6x=0`
    `<=>x=0`
    Vậy…

    `e,` Mk ko rõ đề nên bỏ qua nha.

    $#Blink$ $\boxed{\text{@Rosé}}$

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