a. (a+b-c)=12,b. (a+b-c)=15,c. (a+b-c)=8

By Kylie

a. (a+b-c)=12,b. (a+b-c)=15,c. (a+b-c)=8

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  1. \(\begin{array}{l}
    a\left( {a + b – c} \right) + b\left( {a + b – c} \right) – c\left( {a + b – c} \right) = 12 + 15 – 8\\
    \Leftrightarrow \left( {a + b – c} \right)\left( {a + b – c} \right) = 19\\
    \Leftrightarrow {\left( {a + b – c} \right)^2} = 19\\
    \Rightarrow \left[ \begin{array}{l}
    a + b – c = \sqrt {19} \\
    a + b – c = – \sqrt {19}
    \end{array} \right.\\
    + )\,a + b – c = \sqrt {19} \Rightarrow a = \frac{{12}}{{\sqrt {19} }};b = \frac{{15}}{{\sqrt {19} }};c = \frac{8}{{\sqrt {19} }}\\
    + )a + b – c = – \sqrt {19} \Rightarrow a = – \frac{{12}}{{\sqrt {19} }};b = – \frac{{15}}{{\sqrt {19} }};c = – \frac{8}{{\sqrt {19} }}
    \end{array}\)

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