Bài 1
( x + 6 ) + ( x + 11 ) + …+ ( x + 501 ) = 25450
( x + 4 ) + ( x + 7 ) + ( x + 10 ) + ….+ ( x + 601 ) = 60700
Bài 1 ( x + 6 ) + ( x + 11 ) + …+ ( x + 501 ) = 25450 ( x + 4 ) + ( x + 7 ) + ( x + 10 ) + ….+ ( x + 601 ) = 60700
By Josephine
By Josephine
Bài 1
( x + 6 ) + ( x + 11 ) + …+ ( x + 501 ) = 25450
( x + 4 ) + ( x + 7 ) + ( x + 10 ) + ….+ ( x + 601 ) = 60700
Đáp án:
Giải thích các bước giải:
a, ( x + 6 ) + ( x + 11 ) + …+ ( x + 501 ) = 25450
⇒ 100x + [(501-6)÷5+1]÷2×507= 25 450
⇒ 100x + 25 350 = 25 450
⇒ 100x = 100
⇒ x = 1
b,( x + 4 ) + ( x + 7 ) + ( x + 10 ) + ….+ ( x + 601 ) = 60700
⇒ 200x +{[(601-4)÷3+1]÷2×605 = 60 700
⇒ 200x × 60 500 = 60 700
⇒ 200x = 200
⇒ x = 1
( x + 6 ) + ( x + 11 ) + …+ ( x + 501 ) = 25450
=> x +6 +x+11+…+x+501=25450
=> 100x + (6+11+…+501) =25450
=> 100x + 25350 =25450
=> 100x = 25450 – 25350 = 100
=> x =1
Vậy x = 1
( x + 4 ) + ( x + 7 )+ ( x + 10 )+ …+ ( x + 601 ) = 60700
=> x +4 +x+7+ x + 10+…+x+601= 60700
=> 200x + (4+7+10+…+601) = 60700
=> 200x + 60500 = 60700
=> 200x = 60700 – 60500 = 200
=> x =1
Vậy x = 1