Bài 1: a) (7 . 3^5 – 3^4 + 3^6) : 3^4 b) (16^3 – 64^2) : 8^3 Bài 2 a) (5x^4 – 3x^3 + x^2) : 3x^2 b) (5xy^2 + 9xy – x^2y^2) : (-xy)

Question

Bài 1:
a) (7 . 3^5 – 3^4 + 3^6) : 3^4
b) (16^3 – 64^2) : 8^3
Bài 2
a) (5x^4 – 3x^3 + x^2) : 3x^2
b) (5xy^2 + 9xy – x^2y^2) : (-xy)

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Isabelle 1 năm 2021-12-01T16:58:46+00:00 1 Answers 1 views 0

Answers ( )

    0
    2021-12-01T17:00:01+00:00

    Bài 1 :

    (7.$3^{5}$ – $3^{4}$  + $3^{6}$ ) :$3^{4}$ 

    =$3^{4}$ . ( 21 – 1 + $3^{2}$ )

    =21 – 1 + 9

    =29

    b)

    ($16^{3}$  – $64^{2}$ ) : $8^{3}$ 

    =($8^{4}$ – $8^{4}$) : $8^{3}$ 

    = 0 : $8^{3}$ 

    =0

    Bài 2 :

    a)

    ($5x^{4}$ – $3x^{3}$  + $x^{2}$ ) : $3x^{2}$ 

    =$5x^{4}$ : $3x^{2}$ – $3x^{3}$ : $3x^{2}$ + $x^{2}$ : $3x^{2}$ 

    =$\frac{5}{4}$$x^{2}$ – x + $\frac{1}{3}$ 

    b)

    ($5xy^{2}$ + 9xy – $x^{2}$ $y^{2}$ ) : (- xy)

    = – 5y + ( -1 ) – xy

     

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