Toán Câu 1:TÌm x a,2|1/2 x -1/3|-3/2=1/4 b,4/5-1/2x=1/10 06/09/2021 By Sarah Câu 1:TÌm x a,2|1/2 x -1/3|-3/2=1/4 b,4/5-1/2x=1/10
Câu 1 : a ) 2 |1/2x – 1/3 | -3/2 = 1/4 ⇒ 2| 1/2x – 1/3 | = 1/4 + 3/2 ⇒ 2| 1/2x – 1/3 | = 7/4 ⇒ |1/2x – 1/3 | = 7/4 : 2 = 7/2 ⇒ \(\left[ \begin{array}{l}1/2x- 1/3 = 7/2 \\1/2x – 1/3 = -7/2\end{array} \right.\) ⇒ \(\left[ \begin{array}{l}1/2x= 7/2 + 1/3=23/6 \\1/2x=-7/2 + 1/3= -19/6\end{array} \right.\) ⇒\(\left[ \begin{array}{l}x=23/6 : 1/2= 23/3 \\x=-19/6 : 1/2 = -19/3\end{array} \right.\) Vậy x = 23/3 hoặc x = -19/3 Trả lời
Đáp án: Giải thích các bước giải: Câu 1 a) 2|1/2x-1/3|=1/4+3/2 <=> 2|1/2x-1/3|=7/4 <=> |1/2x-1/3|=7/8 TH1 x>= 2/3 => 1/2x-1/3=7/8 <=> 1/2x=29/24 => x=58/24 TH2 x<2/3 => -1/2x+1/3=7/8 => -1/2x=13/24 => x=-26/24 b) 4/5-1/2x=1/10 <=> 1/2x=4/5-1/10 => 1/2x=7/10 => x=7/5 Trả lời
Câu 1 :
a ) 2 |1/2x – 1/3 | -3/2 = 1/4
⇒ 2| 1/2x – 1/3 | = 1/4 + 3/2
⇒ 2| 1/2x – 1/3 | = 7/4
⇒ |1/2x – 1/3 | = 7/4 : 2 = 7/2
⇒ \(\left[ \begin{array}{l}1/2x- 1/3 = 7/2 \\1/2x – 1/3 = -7/2\end{array} \right.\)
⇒ \(\left[ \begin{array}{l}1/2x= 7/2 + 1/3=23/6 \\1/2x=-7/2 + 1/3= -19/6\end{array} \right.\)
⇒\(\left[ \begin{array}{l}x=23/6 : 1/2= 23/3 \\x=-19/6 : 1/2 = -19/3\end{array} \right.\)
Vậy x = 23/3 hoặc x = -19/3
Đáp án:
Giải thích các bước giải:
Câu 1
a) 2|1/2x-1/3|=1/4+3/2
<=> 2|1/2x-1/3|=7/4
<=> |1/2x-1/3|=7/8
TH1 x>= 2/3
=> 1/2x-1/3=7/8
<=> 1/2x=29/24
=> x=58/24
TH2 x<2/3
=> -1/2x+1/3=7/8
=> -1/2x=13/24
=> x=-26/24
b) 4/5-1/2x=1/10
<=> 1/2x=4/5-1/10
=> 1/2x=7/10
=> x=7/5