cho a + b+ c bằng 0 cmr a mũ 3 + c mũ 3 +b mũ 3 bằng 3abc
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Đáp án:
Giải thích các bước giải:
Ta có:
\(\begin{array}{l}{a^3} + {b^3} + {c^3} – 3abc = \left( {a + b + c} \right)\left( {{a^2} + {b^2} + {c^2} – ab – bc – ac} \right) = 0\\ \Rightarrow {a^3} + {b^3} + {c^3} = 3abc\end{array}\)