## Cho hai đa thức A(x) = 2 x^ 3 + 2 x^2 + 3 x – x + 3 – x = 4 x^ 2 – 6 x^ 2 + 2 x – x + 4;p(x)= 4 x^ 3 – 6 x ^2 + 2 x -x + 4

Question

Cho hai đa thức A(x) = 2 x^ 3 + 2 x^2 + 3 x – x + 3 – x = 4 x^ 2 – 6 x^ 2 + 2 x – x + 4;p(x)= 4 x^ 3 – 6 x ^2 + 2 x -x + 4

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1 tháng 2021-08-12T02:56:00+00:00 1 Answers 0 views 0

$$b)A\left( x \right) + B\left( x \right) = 6{x^3} – 4{x^2} + 3x + 11$$
$$\begin{array}{l} a)A\left( x \right) = 2{x^3} + 2{x^2} + 3x – x + 3 – x + 4{x^2} – 6{x^2} + 2x – x + 4\\ = 2{x^3} + \left( {2 + 4 – 6} \right){x^2} + \left( {3 – 1 – 1 + 2 – 1} \right)x + 7\\ = 2{x^3} + 2x + 7\\ B\left( x \right) = 4{x^3} – 6{x^2} + 2x – x + 4\\ = 4{x^3} – 6{x^2} + x + 4\\ b)A\left( x \right) + B\left( x \right) = 2{x^3} + 2x + 7 + 4{x^3} – 6{x^2} + x + 4\\ = 6{x^3} – 4{x^2} + 3x + 11 \end{array}$$