$\frac{x+1}{2014}$ + $\frac{x+2}{2013}$ + $\frac{x+3}{2012}$ = $\frac{x+10}{2005}$ + $\frac{x+11}{2004}$ + $\frac{x+12}{2003}$ help me

0 bình luận về “$\frac{x+1}{2014}$ + $\frac{x+2}{2013}$ + $\frac{x+3}{2012}$ = $\frac{x+10}{2005}$ + $\frac{x+11}{2004}$ + $\frac{x+12}{2003}$ help me”

1. => $\frac{x+1}{2014}$+1+ $\frac{x+2}{2013}$+1+ $\frac{x+3}{2012}$ +1=$\frac{x+10}{2005}$+1+ $\frac{x+11}{2004}$+1+ $\frac{x+12}{2003}$+1 =>$\frac{x+1}{2014}$+1+ $\frac{x+2}{2013}$+1+ $\frac{x+3}{2012}$ +1-($\frac{x+10}{2005}$+1)- ($\frac{x+11}{2004}$+1)-( $\frac{x+12}{2003}$+1)=0 =>$\frac{x+2015}{2014}$+ $\frac{x+2015}{2013}$+ $\frac{x+2015}{2012}$- $\frac{x+2015}{2005}$- $\frac{x+2015}{2004}$+ $\frac{x+2015}{2003}$=0=>$(x+2015).($ $\frac{1}{2014}$+ $\frac{1}{2013}$+ $\frac{1}{2012}$- $\frac{1}{2005}$- $\frac{1}{2004}$- $\frac{1}{2003}$)=0

   =>$x+2015=0$

   =>$x=-2015

   (Học tốt nhé!)$

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