$\frac{3+2√3}{3}$ + $\frac{2+√2}{√2+1}$ -( 2+ √3)

Question

$\frac{3+2√3}{3}$ + $\frac{2+√2}{√2+1}$ -( 2+ √3)

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Eliza 5 tháng 2021-07-15T11:39:26+00:00 1 Answers 5 views 0

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    2021-07-15T11:40:49+00:00

    Đáp án:$\sqrt{2}$

     

    Giải thích các bước giải:

    =$\frac{3+2\sqrt{3}}{3}+\frac{2+\sqrt{2}}{\sqrt{2}+1}-(2+\sqrt{3})$

    =$\frac{\sqrt{3}(\sqrt{3}+2)}{3}+\frac{\sqrt{2}(\sqrt{2}+1)}{\sqrt{2}+1}-(2+\sqrt{3})$

    =$\sqrt{3}+2+\sqrt{2}-2-\sqrt{3}$

    =$\sqrt{2}$

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