$\frac{(3.4.$2^{16}$}{11. $2^{13}$. $4^{11}$- $16^{9}$}$ Giúp mik với

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$\frac{(3.4.$2^{16}$}{11. $2^{13}$. $4^{11}$- $16^{9}$}$ Giúp mik với

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Charlie 1 tháng 2021-09-13T08:19:47+00:00 2 Answers 7 views 0

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    0
    2021-09-13T08:21:11+00:00

    Có $\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^{9}}$

        =$\frac{3.2^{2}.2^{16}}{11.2^{13}.2^{22}-2^{36}}$

        =$\frac{3.2^{18}}{11.2^{35}-2^{36}}$

        =$\frac{3.2^{18}}{2^{35}.(11-2)}$

        =$\frac{3}{2^{17}.9}$

        =$\frac{1}{2^{17}.3}$

    Vậy giá trị biểu thức là $\frac{1}{2^{17}.3}$

    CHÚC BẠN HOK TỐT!!!!

    0
    2021-09-13T08:21:36+00:00

    `\frac{3.4.2^{16}}{11.2^{13}.4^{11}-16^9}`

    `=\frac{3.2^2 .2^{16}}{11.2^{13}.(2^2)^{11}-(2^4)^9}`

    `=\frac{3.2^{18}}{11.2^{13}.2^{22}-2^{36}}`

    `=\frac{3.2^{18}}{11.2^{35}-2^{36}}`

    `=\frac{3.2^{18}}{2^{18}.(11.2^{17}-2^{18})}`

    `=\frac{3}{11.2^{17}-2^{18}}`

    `=\frac{3}{2^{17}.(11-2)}`

    `=\frac{3}{2^{17}.9}.`

    `=\frac{1}{2^{17}.3}.`

     

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