Giả phương trình (x-1)(x-2)(x-3)(x-4)=(x+1)(x+2)(x+3)(x+4)

0 bình luận về “Giả phương trình (x-1)(x-2)(x-3)(x-4)=(x+1)(x+2)(x+3)(x+4)”

1. (x-1)(x-2)(x-3)(x-4)=(x+1)(x+2)(x+3)(x+4)

   (x^2-2x-x+2)(x-3)(x-4)=(x^2+3x+2)(x+3)(x+4)

   (x^2-3x+2)(x-3)(x-4)=(x^2+3x+2)(x+3)(x+4)

   (x^3-3x^2-3x^2+9x+2x-6)(x-4)=(x^3+3x^2+3x^2+9x+2x+6)(x+4)

   (x^3-6x^2+11x-6)(x-4)=(x^3+6x^2+11x+6)(x+4)

   x^4-4x^3-6x^3+24x^2+11x^2-44x-6x+24=x^4+4x^3+6x^3+24x^2+11x^2+44x+6x+24

   -4x^3-6x^3-44x-6x=4^3+6x^3+44x+6x

   -10x^3-50x=10x^3+50x

   -10x(x^2+5-(-x^2-5))=0

   -10x(2x^2+10)=0

   x(x^2+5)=0

   x=0

   Trả lời