giải pt 96/(x^2-16) +6=(2x-1)/(x+4)+(3x-1)/(x-4)

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giải pt 96/(x^2-16) +6=(2x-1)/(x+4)+(3x-1)/(x-4)

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Mackenzie 1 tháng 2021-08-05T18:05:04+00:00 2 Answers 2 views 0

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    0
    2021-08-05T18:06:07+00:00

    Đáp án: + Giải thích các bước giải:

    `96/(x^2-16) +6=(2x-1)/(x+4)+(3x-1)/(x-4)` 

    `⇔ 96 + 6 ( x^2 – 16 ) = 5x(x+4)`

    `⇔ 6x^2 = 5x^2 – 20x`

    `⇔ 1x^2 – 20x = 0`

    `⇔ x^2 – 20x = 0`

    `⇔ ( x – 0 )( x – 20) = 0`

    `⇔` \(\left[ \begin{array}{l}x-0=0\\x-20=0\end{array} \right.\) 

    `⇔` \(\left[ \begin{array}{l}x=0\\x=20\end{array} \right.\) 

    0
    2021-08-05T18:06:24+00:00

    96/(x²-16) +6=(2x-1)/(x+4)+(3x-1)/(x-4)

    96/(x²-16) +6(x²-16)/(x²-16)=(2x-1)(x-4)/(x²-16)+(3x-1)(x+4)/(x²-16)

    ⇔96 +6(x²-16) =(2x-1)(x-4)+(3x-1)(x+4)

    ⇔96+6x²-96 =2x²-9x+4+3x²+11x-4

    ⇔6x²-5x²-2x=0

    ⇔x²-2x=0⇔x(x-2)=0⇔x=0 hoặc x=2

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