hoa tan het 5 gam hon hop X gom Cu va Fe bang dung dinh HCl du, tao ra 1,12 lit khi H2( o dktc ). tinh% m kim loai trong X

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hoa tan het 5 gam hon hop X gom Cu va Fe bang dung dinh HCl du, tao ra 1,12 lit khi H2( o dktc ). tinh% m kim loai trong X

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Arianna 2 tháng 2021-10-04T11:06:58+00:00 2 Answers 2 views 0

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    0
    2021-10-04T11:08:42+00:00

    $PTPƯ:Fe+2HCl\xrightarrow{} FeCl_2+H_2↑$

    (Lưu ý: Cu không tác dụng với $HCl$)

    $n_{H_2}=\dfrac{1,12}{22,4}=0,05mol.$

    $Theo$ $pt:$ $n_{Fe}=n_{H_2}=0,05mol.$

    $⇒\%m_{Fe}=\dfrac{0,05.56}{5}.100\%=56\%$

    $⇒\%m_{Cu}=100\%-56\%=44\%$

    chúc bạn học tốt!

    0
    2021-10-04T11:08:56+00:00

    $Fe+2HCl\to FeCl_2+H_2$

    $n_{H_2}=\frac{1,12}{22,4}=0,05 mol$

    $\Rightarrow n_{Fe}=0,05 mol$

    $\%m_{Fe}=\frac{0,05.56.100}{5}=56\%$

    $\%m_{Cu}=44\%$

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