Hoàn thành dãy chuyển hóa trên và viết PTHH: Rượu butylic –> Butilen —> Butan —> Metan —> Axetilen —> Etilen —> Etilenglicol —> Brometile

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Hoàn thành dãy chuyển hóa trên và viết PTHH:
Rượu butylic –> Butilen —> Butan —> Metan —> Axetilen —> Etilen —> Etilenglicol —> Brometilen —> Etilen

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Josephine 1 năm 2021-07-12T00:07:21+00:00 2 Answers 31 views 0

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    0
    2021-07-12T00:08:27+00:00

    Bạn tham khảo nha!

    `C_4H_9OH \overset{t^o}\to C_4H_8 + H_2O`

    `C_4H_8 + H_2 \overset{t^o; Ni}\to C_4H_{10}`

    `C_4H_{10} \overset{t^o}\to CH_4 + C_3H_6`

    $2CH_4 \xrightarrow{\text{Làm lạnh nhanh}} C_2H_2 ↑ + 3H_2 ↑$

    `C_2H_2 + H_2 \overset{t^o; PdCO_3; Pd}\to C_2H_4`

    `3C_2H_4 + 2KMnO_4 + 4H_2O \overset{t^o}\to 3C_2H_4(OH)_2 + 2MnO_2 + 2KOH`

    `C_2H_4(OH)_2 + 2HBr -> C_2H_4Br_2 + 2H_2O`

    `C_2H_4Br_2 + Zn \overset{t^o}\to C_2H_4 + ZnBr_2`

    0
    2021-07-12T00:09:02+00:00

    $C_4H_9OH\xrightarrow{170^oC, H^+}C_4H_8+H_2O$

    $C_4H_8+H_2\xrightarrow{t^o,Ni}C_4H_10$
    $C_4H_10\xrightarrow{t^o,xt}CH_4+C_3H_6$

    $2CH_4\xrightarrow{\text{làm lạnh nhanh},1500^oC}C_2H_2+3H_2$
    $C_2H_2+H_2\xrightarrow{t^o,Pd/PdCO_3}C_2H_4$
    $3C_2H_4+2KMnO_4+4H_2O\xrightarrow{}3C_2H_4(OH)_2+2KOH+2MnO_2$

    $C_2H_4(OH)_2+2HBr\xrightarrow{}C_2H_4Br_2+2H_2O$

    $C_2H_4Br_2+Zn\xrightarrow{t^o}ZnBr_2+C_2H_4$

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