Phân tích đa thức sau thành nhân tử : a, 2x ³-8x²+8x b, x ²y-x ³-9y+9x c, 2x ²-3x-5

Question

Phân tích đa thức sau thành nhân tử :
a, 2x ³-8x²+8x
b, x ²y-x ³-9y+9x
c, 2x ²-3x-5

in progress 0
Brielle 1 năm 2021-12-06T19:36:31+00:00 2 Answers 2 views 0

Answers ( )

    0
    2021-12-06T19:38:07+00:00

    a, $2x^3-8x^2+8x=2x(x^2-4x+4)=2x(x-2)^2$

    b, $x^2y-x^3-9y+9x=x^2(y-x)-9(y-x)$

               $=(x^2-9)(y-x)=(x-3)(x+3)(y-x)$

    c, $2x^2-3x-5=2x^2+2x-5x-5$

               $=2x(x+1)-5(x+1)=(2x-5)(x+1)$

    0
    2021-12-06T19:38:19+00:00

    a, 2x ³-8x²+8x

    =2x(x²-4x+4)      

    =2x(x-2)² 

    b, x ²y-x ³-9y+9x

    =(x ²y-x ³)-(9y-9x) 

    =x²(y-x)-9(y-x)

    =(x²-9)(y-x)    

    =(x+3)(x-3)(y-x)

    c, 2x ²-3x-5

    =2x²-2x+5x-5

    =(2x²-2x)+(5x-5)

    =2x(x-1)+5(x-1)

    =(x-1)(2x+5)

Leave an answer

Browse

35:5x4+1-9:3 = ? ( )