Toán rut gon:a)(-48)^3:16^3 b)(-13/8)^3:(-32/13)^4 c)(9/10)^6:(17/-20)^6 07/09/2021 By Adeline rut gon:a)(-48)^3:16^3 b)(-13/8)^3:(-32/13)^4 c)(9/10)^6:(17/-20)^6
Đáp án: \(\begin{array}{l} a)\,\, – 27\\ b)\,\, – \frac{{{{13}^7}}}{{{2^{29}}}}\\ c)\,\,{\left( {\frac{{18}}{{17}}} \right)^6} \end{array}\) Giải thích các bước giải: \(\begin{array}{l} a)\,\,{\left( { – 48} \right)^3}:{16^3} = – {48^3}:{16^3} = – {\left( {\frac{{48}}{{16}}} \right)^3} = – {3^3} = – 27.\\ b)\,\,{\left( { – \frac{{13}}{8}} \right)^3}:{\left( { – \frac{{32}}{{13}}} \right)^4} = – \frac{{{{13}^3}}}{{{8^3}}}.\frac{{{{13}^4}}}{{{{32}^4}}} = – \frac{{{{13}^3}{{.13}^4}}}{{{{\left( {{2^3}} \right)}^3}.{{\left( {{2^5}} \right)}^4}}}\\ = – \frac{{{{13}^7}}}{{{2^9}{{.2}^{20}}}} = – \frac{{{{13}^7}}}{{{2^{29}}}}.\\ c)\,\,{\left( {\frac{9}{{10}}} \right)^6}:{\left( {\frac{{17}}{{ – 20}}} \right)^6} = \frac{{{9^6}}}{{{{10}^6}}}.\frac{{{{20}^6}}}{{{{17}^6}}}\\ = \frac{{{9^6}{{.2}^6}{{.10}^6}}}{{{{10}^6}{{.17}^6}}} = \frac{{{9^6}{{.2}^6}}}{{{{17}^6}}} = \frac{{{{18}^6}}}{{{{17}^6}}} = {\left( {\frac{{18}}{{17}}} \right)^6}. \end{array}\) Trả lời
Đáp án: Giải thích các bước giải: a, 48=16.3 => $\frac{(-48)^3}{16^3}$ = $\frac{-16^3.3^3}{16^3}$ =-3^3 = -27 b, Mình mạnh dạn sửa đề thành 2 phân số nhân với nhau mới rút ra số đẹp đc ^^ ($\frac{-13}{8}$ )$^{3}$ . ($\frac{-32}{13}$ )$^{4}$ $\frac{-(13)^3}{8^3}$ . $\frac{(-32)^4}{13^4}$ = – $\frac{(8.4)^4}{13.8^3}$= – $\frac{8^4.4^4}{13.8^3}$ = – $\frac{8.4^4}{13}$=2048/13( cũng k đẹp lắm) c, ($\frac{9}{10}$ )$^{6}$ : ($\frac{17}{-20}$ )$^{6}$ = $\frac{9^6}{10^6}$ : $\frac{17^6}{(-20)^6}$ = $\frac{9^6}{10^6}$ . $\frac{(-20)^6}{17^6}$ = $\frac{{9^6}2^6}{17^6}$ hay mình nhầm gì k b??? Trả lời
Đáp án:
\(\begin{array}{l} a)\,\, – 27\\ b)\,\, – \frac{{{{13}^7}}}{{{2^{29}}}}\\ c)\,\,{\left( {\frac{{18}}{{17}}} \right)^6} \end{array}\)
Giải thích các bước giải:
\(\begin{array}{l} a)\,\,{\left( { – 48} \right)^3}:{16^3} = – {48^3}:{16^3} = – {\left( {\frac{{48}}{{16}}} \right)^3} = – {3^3} = – 27.\\ b)\,\,{\left( { – \frac{{13}}{8}} \right)^3}:{\left( { – \frac{{32}}{{13}}} \right)^4} = – \frac{{{{13}^3}}}{{{8^3}}}.\frac{{{{13}^4}}}{{{{32}^4}}} = – \frac{{{{13}^3}{{.13}^4}}}{{{{\left( {{2^3}} \right)}^3}.{{\left( {{2^5}} \right)}^4}}}\\ = – \frac{{{{13}^7}}}{{{2^9}{{.2}^{20}}}} = – \frac{{{{13}^7}}}{{{2^{29}}}}.\\ c)\,\,{\left( {\frac{9}{{10}}} \right)^6}:{\left( {\frac{{17}}{{ – 20}}} \right)^6} = \frac{{{9^6}}}{{{{10}^6}}}.\frac{{{{20}^6}}}{{{{17}^6}}}\\ = \frac{{{9^6}{{.2}^6}{{.10}^6}}}{{{{10}^6}{{.17}^6}}} = \frac{{{9^6}{{.2}^6}}}{{{{17}^6}}} = \frac{{{{18}^6}}}{{{{17}^6}}} = {\left( {\frac{{18}}{{17}}} \right)^6}. \end{array}\)
Đáp án:
Giải thích các bước giải:
a, 48=16.3
=> $\frac{(-48)^3}{16^3}$ = $\frac{-16^3.3^3}{16^3}$ =-3^3 = -27
b, Mình mạnh dạn sửa đề thành 2 phân số nhân với nhau mới rút ra số đẹp đc ^^
($\frac{-13}{8}$ )$^{3}$ . ($\frac{-32}{13}$ )$^{4}$
$\frac{-(13)^3}{8^3}$ . $\frac{(-32)^4}{13^4}$
= – $\frac{(8.4)^4}{13.8^3}$= – $\frac{8^4.4^4}{13.8^3}$
= – $\frac{8.4^4}{13}$=2048/13( cũng k đẹp lắm)
c, ($\frac{9}{10}$ )$^{6}$ : ($\frac{17}{-20}$ )$^{6}$
= $\frac{9^6}{10^6}$ : $\frac{17^6}{(-20)^6}$
= $\frac{9^6}{10^6}$ . $\frac{(-20)^6}{17^6}$
= $\frac{{9^6}2^6}{17^6}$
hay mình nhầm gì k b???