Toán rút gọn đa thức^{\frac{1}{5}}xy\left(x+y\right)-2\left(y^3x\:-\:xy^2\right) 12/09/2021 By Eliza rút gọn đa thức^{\frac{1}{5}}xy\left(x+y\right)-2\left(y^3x\:-\:xy^2\right)
`1/5xy(x+y)-2(y^3x-xy^2)` `=1/5x^2y+1/5xy^2-2y^3x+2xy^2` `=xy(1/5x+1/5y-2y^2+2y)` `=xy(1/5x+11/5y-2y^2)` `=1/5x^2y+11/5xy^2-2xy^3.` Trả lời
$\begin{array}{l}{\frac{1}{5}}xy\left(x+y\right)-2\left(y^3x\:-\:xy^2\right)\\=\frac{1}{5}x^{2}y+\frac{1}{5}xy^{2}-2\left ( xy^{3}-xy^{2} \right )\\=\frac{1}{5}x^{2}y+\frac{1}{5}xy^{2}-2xy^{3}+2xy^{2}\\=\frac{1}{5}x^{2}y+\frac{11}{5}xy^{2}-2xy^{3}\end{array}$ Trả lời
`1/5xy(x+y)-2(y^3x-xy^2)`
`=1/5x^2y+1/5xy^2-2y^3x+2xy^2`
`=xy(1/5x+1/5y-2y^2+2y)`
`=xy(1/5x+11/5y-2y^2)`
`=1/5x^2y+11/5xy^2-2xy^3.`
$\begin{array}{l}{\frac{1}{5}}xy\left(x+y\right)-2\left(y^3x\:-\:xy^2\right)\\=\frac{1}{5}x^{2}y+\frac{1}{5}xy^{2}-2\left ( xy^{3}-xy^{2} \right )\\=\frac{1}{5}x^{2}y+\frac{1}{5}xy^{2}-2xy^{3}+2xy^{2}\\=\frac{1}{5}x^{2}y+\frac{11}{5}xy^{2}-2xy^{3}\end{array}$