Ruts gon BT A=3(2^2+1)(2^4+1)(2^8)(2^16+1) Question Ruts gon BT A=3(2^2+1)(2^4+1)(2^8)(2^16+1) in progress 0 Toán Iris 1 năm 2021-08-25T07:55:48+00:00 2021-08-25T07:55:48+00:00 1 Answers 4 views 0
Answers ( )
Đáp án:
A=2^32-1
Giải thích các bước giải:
A=3(2^2+1)(2^4+1)(2^8+1)(2^16+1)
A=3(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^2-1).(2^2+1)(2^4+1)(2^8+1)(2^16+1)
=(2^4-1).(2^4+1)(2^8+1)(2^16+1)
=(2^8-1).(2^8+1)(2^16+1)
=(2^16-1).(2^16+1)
=2^32-1