Toán $\sqrt[]{9-4 căn 2}$ – $\sqrt[]{11+6 căn 2}$ 11/09/2021 By Mary $\sqrt[]{9-4 căn 2}$ – $\sqrt[]{11+6 căn 2}$
$@phamnhuy6a1$ $@gaumatyuki$ $\sqrt[ ]{9-4√2}$ – $\sqrt[ ]{11-6√2}$ = $\sqrt[ ]{8-4√2+1}$ – $\sqrt[ ]{9-6√2+2}$ = $\sqrt[ ]{(2√2)²-2.2√2+1²}$ – $\sqrt[ ]{3²-2.3.√2+(√2)²}$ = $\sqrt[ ]{(2√2-1)²}$ – $\sqrt[ ]{(3-√2)²}$ $= 2√2-1-3-√2$ $= √2-4$ Trả lời
Đáp án:
Giải thích các bước giải:
$@phamnhuy6a1$
$@gaumatyuki$
$\sqrt[ ]{9-4√2}$ – $\sqrt[ ]{11-6√2}$
= $\sqrt[ ]{8-4√2+1}$ – $\sqrt[ ]{9-6√2+2}$
= $\sqrt[ ]{(2√2)²-2.2√2+1²}$ – $\sqrt[ ]{3²-2.3.√2+(√2)²}$
= $\sqrt[ ]{(2√2-1)²}$ – $\sqrt[ ]{(3-√2)²}$
$= 2√2-1-3-√2$
$= √2-4$