Tìm x: (3$\frac{1}{2}$+2x).2$\frac{2}{3}$=5$\frac{1}{3}$

Question

Tìm x:
(3$\frac{1}{2}$+2x).2$\frac{2}{3}$=5$\frac{1}{3}$

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Jasmine 1 tháng 2021-10-28T13:40:42+00:00 2 Answers 3 views 0

Answers ( )

    0
    2021-10-28T13:42:07+00:00

    `(3 1/2 + 2x) . 2 2/3= 5 1/3`

    `(7/2 +2x). 8/3 = 16/3`

    `7/2 +2x=16/3 : 8/3`

    `7/2 +2x=16/3 . 3/8`

    `7/2 +2x=2`

    `2x = 2 – 7/2`

    `<=>2x = (-3)/2`

    `<=> x=(-3)/4`

     

    0
    2021-10-28T13:42:38+00:00

    Đáp án:

     

    Giải thích các bước giải:

    ( 3 $\frac{1}{2}$ ) + 2x ). 2 $\frac{2}{3}$ = 5 $\frac{1}{3}$ 

    ( $\frac{7}{2}$ + 2x ) . $\frac{8}{3}$ = $\frac{16}{3}$ 

     $\frac{7}{2}$ + 2x  = $\frac{16}{3}$ : $\frac{8}{3}$

     $\frac{7}{2}$ + 2x  = 2

         2x = 2 – $\frac{7}{2}$ 

         2x = $\frac{-3}{2}$ 

           x = $\frac{-3}{2}$ : 2

          x = $\frac{-3}{4}$ 

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