Toán Tìm x: (3$\frac{1}{2}$+2x).2$\frac{2}{3}$=5$\frac{1}{3}$ 28/10/2021 By Jasmine Tìm x: (3$\frac{1}{2}$+2x).2$\frac{2}{3}$=5$\frac{1}{3}$
`(3 1/2 + 2x) . 2 2/3= 5 1/3` `(7/2 +2x). 8/3 = 16/3` `7/2 +2x=16/3 : 8/3` `7/2 +2x=16/3 . 3/8` `7/2 +2x=2` `2x = 2 – 7/2` `<=>2x = (-3)/2` `<=> x=(-3)/4` Trả lời
Đáp án: Giải thích các bước giải: ( 3 $\frac{1}{2}$ ) + 2x ). 2 $\frac{2}{3}$ = 5 $\frac{1}{3}$ ( $\frac{7}{2}$ + 2x ) . $\frac{8}{3}$ = $\frac{16}{3}$ $\frac{7}{2}$ + 2x = $\frac{16}{3}$ : $\frac{8}{3}$ $\frac{7}{2}$ + 2x = 2 2x = 2 – $\frac{7}{2}$ 2x = $\frac{-3}{2}$ x = $\frac{-3}{2}$ : 2 x = $\frac{-3}{4}$ Trả lời
`(3 1/2 + 2x) . 2 2/3= 5 1/3`
`(7/2 +2x). 8/3 = 16/3`
`7/2 +2x=16/3 : 8/3`
`7/2 +2x=16/3 . 3/8`
`7/2 +2x=2`
`2x = 2 – 7/2`
`<=>2x = (-3)/2`
`<=> x=(-3)/4`
Đáp án:
Giải thích các bước giải:
( 3 $\frac{1}{2}$ ) + 2x ). 2 $\frac{2}{3}$ = 5 $\frac{1}{3}$
( $\frac{7}{2}$ + 2x ) . $\frac{8}{3}$ = $\frac{16}{3}$
$\frac{7}{2}$ + 2x = $\frac{16}{3}$ : $\frac{8}{3}$
$\frac{7}{2}$ + 2x = 2
2x = 2 – $\frac{7}{2}$
2x = $\frac{-3}{2}$
x = $\frac{-3}{2}$ : 2
x = $\frac{-3}{4}$