Tìm x : a) (19.|x-1|+ 2 . $5^{2}$) : 14 = ( $(13-8)^{2}$ – $4^{2}$

Question

Tìm x :
a) (19.|x-1|+ 2 . $5^{2}$) : 14 = ( $(13-8)^{2}$ – $4^{2}$

in progress 0
Isabelle 2 tháng 2021-10-20T03:17:27+00:00 2 Answers 4 views 0

Answers ( )

    0
    2021-10-20T03:18:49+00:00

    @Bơ

    `(19.|x-1|+2.5^2):14=((13-8)^2-4^2)`
    `(19.|x-1|+2.5^2):14=5^2-4^2`
    `(19.|x-1|+2.5^2):14=25-16`
    `(19.|x-1|+2.5^2):14=9`
    `(19.|x-1|+2.25):14=9`
    `19.|x-1|+50=126`
    `19.|x-1|=238-50`
    `19.|x-1|=76`
    `|x-1|=76:19`
    `|x-1|=4`
    `=>x-1=4 \text{hay}x-1=-4`
    `=>x=4+1\text{hay}x=-4+1`
    `=>x=5\text{hay}x=-3`

     

    0
    2021-10-20T03:18:58+00:00

    a, (19.|x-1|+2.5^2):14 = (13-8)^2 – 4^2

    (19|x-1|+2.25):14=5^2-16

    (19|x-1|+50):14=25-16

    (19|x-1|+50):14=9

    19|x-1|+50=9.14

    19|x-1|+50=126

    19|x-1|=126-50

    19|x-1|=76

    |x-1|=76:19

    |x-1|=4

    => x-1=4 hoặc x-1=-4

    => x=4+1 hoặc x=-4+1

    => x=5 hoặc x=-3

    Vậy x ∈ {-3;5}

Leave an answer

Browse

35:5x4+1-9:3 = ? ( )