Tìm x a,2^3.x+5^2.x=2.5^2+2^3-33 b,15:x+2=3^3+3:10 c,2^2+3.x-5+14+5^2+124:2^2

Question

Tìm x
a,2^3.x+5^2.x=2.5^2+2^3-33
b,15:x+2=3^3+3:10
c,2^2+3.x-5+14+5^2+124:2^2

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Mackenzie 3 tuần 2021-08-13T13:55:29+00:00 2 Answers 0 views 0

Answers ( )

    0
    2021-08-13T13:56:29+00:00

    Đáp án:

     

    Giải thích các bước giải:

    a)2³.x+5².x=2.5²+2³-33

    x.(8+25)=2.25+8-33

    x.33=50+8-33

    33x=25

    x=25/33

    b)15:x+2=3³+3:10

    15:x+2=27+3:10

    15:x+2=27+0,3

    15:x+2=27,3

    15:x=27,3-2=25,3

    x=15:25,3=15/25,3

    c)2²+3.x-5+14+5²+124:2²

    (sai đề phải ko?)

    0
    2021-08-13T13:56:29+00:00

    a,2³.x+5².x=2.5²+2³-33

    ⇔ x(2³ + 5²) = 2 . 25 + 8 – 33

    ⇔ x . (8 + 10) = 25

    ⇔ x . 18 = 25

    ⇔ x = $\frac{25}{18}$ 

    b,15:x+2=3³+3:10

    ⇔ 15 : x = 3³ + 3 : 10 – 2

    ⇔ 15 : x = $\frac{250}{10}$ 

    ⇔ x = $\frac{3}{5}$

    c,2² + 3.x – 5 + 14 + 5² + 124 : 2²

                             ???

    Phần c sai đề ak?

     

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