tìm x biết a) 13x(x-2019)-x+2019=0 9x^2-9x=0

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tìm x biết
a) 13x(x-2019)-x+2019=0
9x^2-9x=0

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Maya 1 tuần 2021-12-04T16:48:46+00:00 2 Answers 1 views 0

Answers ( )

    0
    2021-12-04T16:50:33+00:00

    Đáp án:

    a,

    $13x(x-2019)-x+2019=0$

    $\to 13x(x-2019)-(x-2019)=0$

    $\to (x-2019)(13x-1)=0$

    $\to \left[\begin{array}{l}x-2019=0\\13x-1=0\end{array}\right.$

    $\to \left[\begin{array}{l}x=2019\\x=\dfrac{1}{13}\end{array}\right.$  

    b,

    $9x^2-9x=0$

    $\to 9x(x-1)=0$

    $\to \left[\begin{array}{l}9x=0\\x-1=0\end{array}\right.$

    $\to \left[\begin{array}{l}x=0\\x=1\end{array}\right.$

    0
    2021-12-04T16:50:38+00:00

    $13x(x-2019)-x+2019=0$

    $⇔13x(x-2019)-(x-2019)=0$

    $⇔(13x-1)(x-2019)=0$

    $⇔\left[ \begin{array}{1}13x=1\\x=2019\end{array} \right.$

    $⇔\left[ \begin{array}{1}x=\dfrac{1}{13}\\x=2019\end{array} \right.$

    $9x^2-9x=0$

    $⇔9x(x-1)=0$

    $⇔\left[ \begin{array}{1}x=0\\x=1\end{array} \right.$

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