Toán tính : 5.4^15.9^9-4.3^20.8^9 phần 5.29.6^19-7.2^29.27^6 11/09/2021 By Mary tính : 5.4^15.9^9-4.3^20.8^9 phần 5.29.6^19-7.2^29.27^6
Giải thích các bước giải: $\dfrac{5\cdot 4^{15}\cdot 9^9-4\cdot 3^{20}\cdot 8^9}{5\cdot 2^9\cdot 6^{19}-7\cdot 2^{29}\cdot 27^6}$ $=\dfrac{5\cdot (2^2)^{15}\cdot (3^2)^9-4\cdot 3^{20}\cdot (2^3)^9}{5\cdot 2^9\cdot (2\cdot 3)^{19}-7\cdot 2^{29}\cdot (3^3)^6}$ $=\dfrac{5\cdot 2^{30}\cdot 3^{18}-4\cdot 3^{20}\cdot 2^{27}}{5\cdot 2^9\cdot 2^{19}\cdot 3^{19}-7\cdot 2^{29}\cdot 3^{18}}$ $=\dfrac{5\cdot 2^{30}\cdot 3^{18}-2^2\cdot 3^{20}\cdot 2^{27}}{5\cdot 2^{28}\cdot 3^{19}-7\cdot 2^{29}\cdot 3^{18}}$ $=\dfrac{5\cdot 2^{30}\cdot 3^{18}- 3^{20}\cdot 2^{29}}{5\cdot 2^{28}\cdot 3^{19}-7\cdot 2^{29}\cdot 3^{18}}$ $=\dfrac{2^{29}\cdot 3^{18}(5\cdot 2- 3^{2})}{2^{28}\cdot 3^{18}\cdot (5\cdot 3-2\cdot 7)}$ $=\dfrac{2^{29}\cdot 3^{18}\cdot 1}{2^{28}\cdot 3^{18}\cdot 1}$ $=2$ Trả lời
Đáp án+Giải thích các bước giải: $\\\dfrac{5. 4^{15}. 9^9-4.3^{20}. 8^9}{5.2^9. 6^{19}-7. 2^{29}. 27^6}\\=\dfrac{5. 2^{30}. 3^{18}-4. 3^{20}. 2^{27}}{5. 2^9. 2^{19}. 3^{19}-7. 2^{29}. 3^{18}}\\=\dfrac{5. 2^{30}. 3^{18}-. 3^{20}. 2^{29}}{5. 2^{28}. 3^{19}-7. 2^{29}. 3^{18}}\\==\dfrac{2^{29}. 3^{18}(5.2- 3^{2})}{2^{28}. 3^{18}.(5. 3-2.7)}\\=\dfrac{2^{29}. 3^{18}. 1}{2^{28}. 3^{18}.1}\\=2$ Trả lời
Giải thích các bước giải:
$\dfrac{5\cdot 4^{15}\cdot 9^9-4\cdot 3^{20}\cdot 8^9}{5\cdot 2^9\cdot 6^{19}-7\cdot 2^{29}\cdot 27^6}$
$=\dfrac{5\cdot (2^2)^{15}\cdot (3^2)^9-4\cdot 3^{20}\cdot (2^3)^9}{5\cdot 2^9\cdot (2\cdot 3)^{19}-7\cdot 2^{29}\cdot (3^3)^6}$
$=\dfrac{5\cdot 2^{30}\cdot 3^{18}-4\cdot 3^{20}\cdot 2^{27}}{5\cdot 2^9\cdot 2^{19}\cdot 3^{19}-7\cdot 2^{29}\cdot 3^{18}}$
$=\dfrac{5\cdot 2^{30}\cdot 3^{18}-2^2\cdot 3^{20}\cdot 2^{27}}{5\cdot 2^{28}\cdot 3^{19}-7\cdot 2^{29}\cdot 3^{18}}$
$=\dfrac{5\cdot 2^{30}\cdot 3^{18}- 3^{20}\cdot 2^{29}}{5\cdot 2^{28}\cdot 3^{19}-7\cdot 2^{29}\cdot 3^{18}}$
$=\dfrac{2^{29}\cdot 3^{18}(5\cdot 2- 3^{2})}{2^{28}\cdot 3^{18}\cdot (5\cdot 3-2\cdot 7)}$
$=\dfrac{2^{29}\cdot 3^{18}\cdot 1}{2^{28}\cdot 3^{18}\cdot 1}$
$=2$
Đáp án+Giải thích các bước giải:
$\\\dfrac{5. 4^{15}. 9^9-4.3^{20}. 8^9}{5.2^9. 6^{19}-7. 2^{29}. 27^6}\\=\dfrac{5. 2^{30}. 3^{18}-4. 3^{20}. 2^{27}}{5. 2^9. 2^{19}. 3^{19}-7. 2^{29}. 3^{18}}\\=\dfrac{5. 2^{30}. 3^{18}-. 3^{20}. 2^{29}}{5. 2^{28}. 3^{19}-7. 2^{29}. 3^{18}}\\==\dfrac{2^{29}. 3^{18}(5.2- 3^{2})}{2^{28}. 3^{18}.(5. 3-2.7)}\\=\dfrac{2^{29}. 3^{18}. 1}{2^{28}. 3^{18}.1}\\=2$