tinh the tich khi o dktc can thiet de dieu che 5.6 l hcl hieu suat dat 80%

Question

tinh the tich khi o dktc can thiet de dieu che 5.6 l hcl hieu suat dat 80%

in progress 0
Kaylee 3 tuần 2021-11-21T04:29:22+00:00 2 Answers 4 views 0

Answers ( )

    0
    2021-11-21T04:30:37+00:00

    Đáp án:

     3,5 l

    Giải thích các bước giải:

    \(\begin{array}{l}
    {H_2} + C{l_2} \to 2HCl\\
    nHCl = \frac{{5,6}}{{22,4}} = 0,25\,mol\\
     =  > n{H_2} = nC{l_2} = 0,125\,mol\\
    V{H_2} = VC{l_2} = \frac{{0,125 \times 22,4}}{{80\% }} = 3,5l
    \end{array}\)

    0
    2021-11-21T04:31:16+00:00

    \[H_2+Cl_2\to 2HCl\]

    \[n_{HCl}=\dfrac{5,6}{22,4}=0,25(mol)\]

    \[\to n_{H_2}=n_{Cl_2}=\dfrac{0,25}{2}=0,125(mol)\]

    \[\to V_{H_2}=V_{Cl_2}=\dfrac{0,125\times 22,4}{80\%}=3,5(l)\]

Leave an answer

Browse

35:5x4+1-9:3 = ? ( )