Divide $132 into 3 parts such that the second part is 2/3 of the third part and the ratio between the first and the third parts is 3:7. The third part is ….
Divide $132 into 3 parts such that the second part is 2/3 of the third part and the ratio between the first and the third parts is 3:7. The third part is ….
Call x y z respectively are bag 1, bag 2 ,bag 3 ( x y z > 0)
We have:
y = 2/3 z => y/2 = z/3 = y/14 = z/21
The ratio of x and z is 3/7 => x/3 = z/7 => x/9 = z/21
Apply an equal quality range ratio. we have:
x/9 + y/14 + z/21 = 132 = x+y+z / 9 + 14 + 21 = 132/ 44 = 3
=> x = 27$
=> y = 42$
=> z = 63$
gọi 3 phần là a,b,c
Theo bài ra, ta có
$\frac{b}{c}$=$\frac{2}{3}$ =$\frac{14}{21}$
$\frac{a}{c}$=$\frac{3}{7}$ =$\frac{9}{21}$
⇒a chiềm 9 phần, b chiếm 14 phần, c chiếm 21 phần
Phần thứ ba= 132:(9+14+21)*21=63
(no copy)