1) (2x – 1/3)^3 2) (1/3x + 1)^3 3) 16 – 8x + x^2 4) x^3 – 6x + 12x – 8 Giúp Em với ạ

1) (2x – 1/3)^3
2) (1/3x + 1)^3
3) 16 – 8x + x^2
4) x^3 – 6x + 12x – 8
Giúp Em với ạ

0 bình luận về “1) (2x – 1/3)^3 2) (1/3x + 1)^3 3) 16 – 8x + x^2 4) x^3 – 6x + 12x – 8 Giúp Em với ạ”

  1. 1)(2x-1/3)³

    =(2x)³- 3 . (2x)².1/3 + 3 . 2x . 1/3²-1/3³

    =8 – 4x² + 2/9x-1/27

    2) (1/3x + 1)³

    =(1/3x)³ + 3.(1/3x)².1+ 3.1/3x.1²+1³

    =1/27+1/9x²+x+1

    =28/7+1/9x²+x

    3) 16 – 8x + x^2

    =4²-2.4.x+x²

    =(4-x)²

    4) x³ – 6x + 12x – 8

    =x³-3.x².2+3.x.2²-2³

    =(x-2)³

    chúc bạn học tốt :)))

    Bình luận
  2. `1,(2x-1/3)³`

    `=(2x)³- 3 . (2x)².1/3 + 3 . 2x . 1/3²-1/3³`

    `=8 – 4x² + 2/9x-1/27`

    `2,(1/3x + 1)³`

    `=(1/3x)³ + 3.(1/3x)².1+ 3.(1/3x).1²+1³`

    `=1/27+1/9x²+x+1`

    `=28/7+1/9x²+x`

    `3,16 – 8x + x^2`

    `=4²-2.4.x+x²`

    `=(4-x)²`

    `4,x³ – 6x + 12x – 8`

    `=x³-3.x².2+3.x.2²-2³`

    `=(x-2)³`

    Xin hay nhất !

     

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