1. 2. 3
a) CH4 —-> C2H2—-> C2H4—–> C2H5OH
1. 2. 3
b) C2H2—->C4H4—–> C4H6—–> polibutadien
1. 2. 3
a) CH4 —-> C2H2—-> C2H4—–> C2H5OH
1. 2. 3
b) C2H2—->C4H4—–> C4H6—–> polibutadien
a,
(1) $2CH_4 \buildrel{{1500^oC}}\over\to C_2H_2+ 3H_2$
(2) $C_2H_2+ H_2 \buildrel{{Pd/PbCO_3, t^o}}\over\to C_2H_4$
(3) $C_2H_4+ H_2O \buildrel{{H^+, t^o}}\over\to C_2H_5OH$
b,
(1) $2C_2H_2 \buildrel{{CuCl_2, t^o}}\over\to CH\equiv C-CH=CH_2$
(2) $CH\equiv C-CH=CH_2+ H_2 \buildrel{{Pd/PbCO_3, t^o}}\over\to CH_2=CH-CH=CH_2$
(3) $nCH_2=CH-CH=CH_2 \buildrel{{t^o, xt, p}}\over\to (CH_2-CH=CH-CH_2)_n$
a)
\(2C{H_4}\xrightarrow{{{{1500}^o}C}}{C_2}{H_2} + 3{H_2}\)
\({C_2}{H_2} + {H_2}\xrightarrow{{{t^o},Pd}}{C_2}{H_4}\)
\({C_2}{H_4} + {H_2}O\xrightarrow{{{H_2}S{O_4},{t^o}}}{C_2}{H_5}OH\)
b)
\(2{C_2}{H_2}\xrightarrow{{{t^o}}}CH \equiv C – CH = C{H_2}\)
\(CH \equiv C – CH = C{H_2} + {H_2}\xrightarrow{{Pd,{t^o}}}C{H_2} = CH – CH = C{H_2}\)
\(nC{H_2} = CH – CH = C{H_2}\xrightarrow{{{t^o},xt}}{( – C{H_2} – CH = CH – C{H_2} – )_n}\)