1/ ( x^2-5) (x+3) 2/(x+4) (x-x^2) 3/ (12x-5) (4x-1) 4/(3x-7) (1-16x) 30/07/2021 Bởi Eva 1/ ( x^2-5) (x+3) 2/(x+4) (x-x^2) 3/ (12x-5) (4x-1) 4/(3x-7) (1-16x)
1/ ( x²-5) (x+3) = x³+3x²-5x+15 2/ (x+4) (x-x²) = x²-x³+4x-4x² = 2x²-x³+4x 3/ (12x-5) (4x-1) = 48x²-12x-20x+5 = 48x²-32x+5 4/(3x-7) (1-16x) = 3x-18x²-7+112x = 115x-18x²-7 Bình luận
Đáp án: Giải thích các bước giải: $1/ (x^2-5)(x+3)$ $=x^2(x+3)-5(x+3)$ $=x^3+3x^2-5x-15$ $2/ (x+4)(x-x^2)$ $=x(x-x^2)+4(x-x^2)$ $=x^2-x^3+4x-4x^2$ $=4x-x^3-3x^2$ $3/ (12x-5)(4x-1)$ $=12x(4x-1)-5(4x-1)$ $=48x^2-12x-20x+5$ $=48x^2-32x+5$ $4/ (3x-7)(1-16x)$ $=3x(1-16x)-7(1-16x)$ $=3x-48x^2-7+102x$ $=105x-48x^2-7$ Bình luận
1/ ( x²-5) (x+3)
= x³+3x²-5x+15
2/ (x+4) (x-x²)
= x²-x³+4x-4x²
= 2x²-x³+4x
3/ (12x-5) (4x-1)
= 48x²-12x-20x+5
= 48x²-32x+5
4/(3x-7) (1-16x)
= 3x-18x²-7+112x
= 115x-18x²-7
Đáp án:
Giải thích các bước giải:
$1/ (x^2-5)(x+3)$
$=x^2(x+3)-5(x+3)$
$=x^3+3x^2-5x-15$
$2/ (x+4)(x-x^2)$
$=x(x-x^2)+4(x-x^2)$
$=x^2-x^3+4x-4x^2$
$=4x-x^3-3x^2$
$3/ (12x-5)(4x-1)$
$=12x(4x-1)-5(4x-1)$
$=48x^2-12x-20x+5$
$=48x^2-32x+5$
$4/ (3x-7)(1-16x)$
$=3x(1-16x)-7(1-16x)$
$=3x-48x^2-7+102x$
$=105x-48x^2-7$