1. X^2/căn 3x-2. -căn3x-2 = 1-x 2. Căn2x^2-1+căn x^2-3x-2=căn2x^2+2x+3 + Căn x^2-x+2

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1. Giải thích các bước giải:

   1,

   ĐKXĐ:  \(x \ge \frac{2}{3}\)

   \[\begin{array}{l}
   \frac{{{x^2}}}{{\sqrt {3x – 2} }} – \sqrt {3x – 2}  = 1 – x\\
    \Leftrightarrow \frac{{{x^2} – {{\sqrt {3x – 2} }^2}}}{{\sqrt {3x – 2} }} + x – 1 = 0\\
    \Leftrightarrow \frac{{{x^2} – 3x + 2}}{{\sqrt {3x – 2} }} + x – 1 = 0\\
    \Leftrightarrow \left( {x – 1} \right)\left( {\frac{{x – 2}}{{\sqrt {3x – 2} }} + 1} \right) = 0\\
    \Leftrightarrow \left[ \begin{array}{l}
   x = 1\\
   2 – x = \sqrt {3x – 2} 
   \end{array} \right.\\
    \Leftrightarrow \left[ \begin{array}{l}
   x = 1\\
   \left\{ \begin{array}{l}
   x \le 2\\
   {x^2} – 4x + 4 = 3x – 2
   \end{array} \right.
   \end{array} \right. \Leftrightarrow \left[ \begin{array}{l}
   x = 1\\
   x = 6
   \end{array} \right.\left( {t/m} \right)
   \end{array}\]

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