1/ (x ²-2xy+y ²) (x-y) 2/ (x ²+2xy+y ²) (x+y) 3/ (3x-5) (2x+11)-(2x+3) (3x+7) 4/ y(y ³+y ²-3y-2)+(y ²-2) (y ²+y-1) 5/ 6x ²-(2x+5) (3x-2)

1/ (x ²-2xy+y ²) (x-y)
2/ (x ²+2xy+y ²) (x+y)
3/ (3x-5) (2x+11)-(2x+3) (3x+7)
4/ y(y ³+y ²-3y-2)+(y ²-2) (y ²+y-1)
5/ 6x ²-(2x+5) (3x-2)

0 bình luận về “1/ (x ²-2xy+y ²) (x-y) 2/ (x ²+2xy+y ²) (x+y) 3/ (3x-5) (2x+11)-(2x+3) (3x+7) 4/ y(y ³+y ²-3y-2)+(y ²-2) (y ²+y-1) 5/ 6x ²-(2x+5) (3x-2)”

  1. 1/ (x ²-2xy+y ²) (x-y)

    = ( x – y )² ( x – y )

    = ( x – y )³

    2/ (x ²+2xy+y ²) (x+y)

    = ( x + y )² ( x + y )

    = ( x + y )³

    3/ (3x-5) (2x+11)-(2x+3) (3x+7)

    = 6x² + 33x – 10x – 55 – 6x² – 14x  – 9x – 21

    = -76

    4/ y(y ³+y ²-3y-2)+(y ²-2) (y ²+y-1)

    = $y^{4}$ + y³ – 3y² – 2y + $y^{4}$ + y³ – y² – 2y² – 2y + 2

    = $2y^{4}$ + 2y³ – 4y² – 4y + 2

    5/ 6x ²-(2x+5) (3x-2)

    = 6x² – 6x² + 4x – 15x + 10

    = -11x + 10

    Xin ctlhn ạ!

     

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  2. $1/(x^{2}-2xy+y^{2})(x-y)\\=(x-y)^{2}(x-y)\\=(x-y)^{3}\\2/(x^{2}+2xy+y^{2})(x+y)\\=(x+y)^{2}(x+y)\\=(x+y)^{3}\\3/(3x-5)(2x+11)-(2x+3)(3x+7)\\=6x^{2}+33x-10x-55-(6x^{2}+14x+9x+21)\\=6x^{2}+33x-10x-55-(6x^{2}+23x+21)\\=6x^{2}+33x-10x-55-6x^{2}-23x-21\\=0-76=-76\\4/y(y^{3}+y^{2}-3y-2)+(y^{2}-2).(y^{2}+y-1)\\=y^{4}+y^{3}-3y^{2}-2y+y^{4}+y^{3}-y^{2}-2y^{2}-2y+2\\=2y^{4}+2y^{3}-6y^{2}-4y+2\\5/6x^{2}-(2x+5)(3x-2)\\=6x^{2}-(6x^{2}-4x+15x-10)\\=6x^{2}-(6x^{2}+11x-10)\\=6x^{2}-6x^{2}-11x+10\\=-11x+10$

     

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