[-1/3] mux2 +[-1/3] mux3*27+[-2017/2018]

Đáp án:

$\begin{array}{l}
{\left( { – \frac{1}{3}} \right)^2} + {\left( { – \frac{1}{3}} \right)^3}.27 + \left( { – \frac{{2017}}{{2018}}} \right)\\
 = \frac{1}{9} – \frac{1}{{{3^3}}}{.3^3} – \frac{{2017}}{{2018}}\\
 = \frac{1}{9} – 1 – \frac{{2017}}{{2018}}\\
 = \frac{{2018 – 9.2018 – 9.2017}}{{18162}}\\
 = \frac{{ – 34297}}{{18162}}
\end{array}$