(1/3×5+1/5×7+1/7×9+…..+1/19×21) x X =9/7 09/08/2021 Bởi Caroline (1/3×5+1/5×7+1/7×9+…..+1/19×21) x X =9/7
$(\dfrac{1}{3.5}+\dfrac{1}{5.7}+…+\dfrac{1}{19.21}).x=\dfrac{9}{7}$ $\dfrac{1}{2}.(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+…+\dfrac{1}{19}-\dfrac{1}{21}).x=\dfrac{9}{7}$ $\dfrac{1}{2}.(\dfrac{1}{3}-\dfrac{1}{21}).x=\dfrac{9}{7}$ $\dfrac{1}{2}.\dfrac{2}{7}.x=\dfrac{9}{7}$ $\dfrac{1}{7}.x=\dfrac{9}{7}$ $x=\dfrac{9}{7}:\dfrac{1}{7}=\dfrac{9}{7}.7=9$ Vậy $x=9$ Bình luận
`(1/(3×5)+1/(5×7)+1/(7×9)+…+1/(19×21))×x = 9/7` `1/2 ×(2/(3×5)+2/(5×7)+2/(7×9)+…+2/(19×21))×x= 9/7` `1/2 ×(1/(3×5)+1/(5×7)+1/(7×9)+…+1/(19×21))×x= 9/7` `1/2 ×(1/3 -1/5 +1/5 -1/7 +1/7 -1/9 +1/9 -… -1/19 + 1/19 -1/21)×x= 9/7` `1/2 ×[1/3 +(1/5 -1/5)+(1/7 -1/7)+(1/9-1/9)+…+(1/19 -1/19)-1/21]×x= 9/7` `1/2 ×(1/3 +0+0+0+…+0 -1/21×)x= 9/7` `1/2 ×(1/3 -1/21)×x= 9/7` `1/2 ×(7/21 -1/21)×x= 9/7` `1/2 × 6/21 ×x= 9/7` `1/2 × 2/7 ×x= 9/7` `(1×2)/(2×7) ×x= 9/7` `1/7 ×x= 9/7` `x= 9/7 : 1/7` `x= 9/7 × 7` `x=(9×7)/7` `x=9` chúc học tốt Bình luận
$(\dfrac{1}{3.5}+\dfrac{1}{5.7}+…+\dfrac{1}{19.21}).x=\dfrac{9}{7}$
$\dfrac{1}{2}.(\dfrac{1}{3}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{7}+…+\dfrac{1}{19}-\dfrac{1}{21}).x=\dfrac{9}{7}$
$\dfrac{1}{2}.(\dfrac{1}{3}-\dfrac{1}{21}).x=\dfrac{9}{7}$
$\dfrac{1}{2}.\dfrac{2}{7}.x=\dfrac{9}{7}$
$\dfrac{1}{7}.x=\dfrac{9}{7}$
$x=\dfrac{9}{7}:\dfrac{1}{7}=\dfrac{9}{7}.7=9$
Vậy $x=9$
`(1/(3×5)+1/(5×7)+1/(7×9)+…+1/(19×21))×x = 9/7`
`1/2 ×(2/(3×5)+2/(5×7)+2/(7×9)+…+2/(19×21))×x= 9/7`
`1/2 ×(1/(3×5)+1/(5×7)+1/(7×9)+…+1/(19×21))×x= 9/7`
`1/2 ×(1/3 -1/5 +1/5 -1/7 +1/7 -1/9 +1/9 -… -1/19 + 1/19 -1/21)×x= 9/7`
`1/2 ×[1/3 +(1/5 -1/5)+(1/7 -1/7)+(1/9-1/9)+…+(1/19 -1/19)-1/21]×x= 9/7`
`1/2 ×(1/3 +0+0+0+…+0 -1/21×)x= 9/7`
`1/2 ×(1/3 -1/21)×x= 9/7`
`1/2 ×(7/21 -1/21)×x= 9/7`
`1/2 × 6/21 ×x= 9/7`
`1/2 × 2/7 ×x= 9/7`
`(1×2)/(2×7) ×x= 9/7`
`1/7 ×x= 9/7`
`x= 9/7 : 1/7`
`x= 9/7 × 7`
`x=(9×7)/7`
`x=9`
chúc học tốt